Lagrange Multipliers: Examples


1. Find the minimum value of the following function, subject to the constraint shown afterwards:
MATH

MATH


Solution:

Let MATH. Then use the formula shown below to set up the system of equations:
MATH

The system is then:
MATH

MATH

MATH

MATH

The solution of this system is $x=3,y=-9,$ and $z=-4.$ Thus the optimum value is:
MATH

 


2. Let MATH represent the temperature at each point on the sphere MATH. Find the extreme temperatures on the curve formed by the intersection of the plane $x+y+z=3$ and the sphere.

 

Solution:

 The constraints are:
MATH

MATH


The formula for two constraints is:
MATH


Thus we can set of the following system of equations:


MATH


MATH


MATH


MATH


MATH


Solving the system of equations (try this on your own) tells us that $\lambda =0$ or $x=y$. If $\lambda =0$, then we get the critical points: $(3,-1,1)$

and $(-1,3,1)$. If $x=y,$then we get the critical points MATH and MATH.Thus, putting the points in T

tells us the temperatures at the four critical points:


MATH


MATH


MATH

Which tells us that 25 is a minimum and 30.33 is a maximum.

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