The Chain Rule: Examples
1. Find dw/dt when dw is as follows: w=x^2*y-y^2 x=sin(t) y=exp(t)
Anwser:
To find this, we must use the chain rule, then just use the diff function:
| > | diff(x^2*y-y^2,x)*diff(sin(t),t)+diff(x^2*y-y^2,y)*diff(exp(t),t); |
2. Find dw/dt and dw/ds when the functions are as follows: w=2*x*y x=s^2+t^2 y=s/t
Anwser
To find dw/dt we can find all of partial derivatives we need using the diff command:
| > | diff(2*x*y,x)*diff(s^2+t^2,t)+diff(2*x*y,y)*diff(s/t,t); |
Then we substiute in the x and y values and simplify:
| > | eval(%,[x=s^2+t^2,y=s/t]); |
| > | simplify(%); |
To find dw/ds we hold t constant and use the diff command to do the chain rule:
| > | diff(2*x*y,x)*diff(s^2+t^2,s)+diff(2*x*y,y)*diff(s/t,s); |
Then we substiute in the x and y values and simplify:
| > | eval(%,[x=s^2+t^2,y=s/t]); |
| > | simplify(%); |