Some important concept about greatest common divisor for![]()
We have proved that
.
The statement above is one way implication. You can not use a linear combination of
to imply the greatest
common divisor of
, unless you can claim the linear combination is the smallest
positive integer among
that is the set we
considered during the proof. We started
with let
be the smallest element in
and then we showed
that ![]()
Prove that ![]()
(The following “wrong” argument could easily happened)
Assume that
, then ![]()
i.e.
. Then
.
(The last line above is not
necessarily true, unless you can prove
presents the smallest
positive integer among the positive integers that can be presented by integral
linear combination of
)